what are the possible expressions for the dimensions of the cuboids whose volumes are given below
a)
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Answered by
4
Explanation:
Volume = 12ky2 + 8ky - 20k
= 4k (3y2 + 2y - 5)
= 4k (3y2 + 5y -3y - 5)
= 4k (y (3y+5) - 1(3y+5))
= 4k (3y +5) (y-1)
Dimensions are l = 4k, b = 3y+5, h = y-1
Answered by
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volume is given by:- 12ky² + 8ky - 20k
to find :- dimension of the cuboid
soln=
volume of cuboid = l×b×h
12ky²+8ky-20k
k(12y²+8y-20)
4k(3y²+2y-5)
4k(3y²+5y-3y-5)
4k(3y(y-1)+5(y-1))
4k((y-1)(3y+5))
length = 4k
breadth = (y-1)
height=(3y+5)
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