Math, asked by Sutemater, 6 months ago

What are the possible expressions for the dimensions of the cuboids whose volumes are given below? 

(i) Volume : 3x²–12x

(ii) Volume : 12ky²+8ky–20k

Answers

Answered by meghjaiswal29
42

Answer:

Step-by-step explanation:

Problem based on geometrical figure:

First we determine all the factors of the given polynomial by splitting middle term and then consider any of the factor as any of the dimension.

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Solution:

 

(i) Volume : 3x² – 12x

Since, volume is product of length, breadth and height therefore by factorizing the given volume, we can know the length, breadth and height of the cuboid.

3x²– 12x

= 3x(x – 4)

 

Hence,possible expression for length = 3

Possible expression for breadth = x

Possible expression for height = (x – 4)

 

(ii) Volume : 12ky² + 8ky – 20k

Since, volume is product of length, breadth and height therefore by factorizing the given volume, we can know the length, breadth and height of the cuboid.

12ky² + 8ky – 20k

= 4k(3y² + 2y – 5)

[By middle term splitting]

= 4k(3y² +5y-3y-5)

= 4k[y(3y+5)-1(3y+ 5)]

= 4k (3y +5) (y – 1)

 

Hence,possible expression for length = 4k

Possible expression for breadth = (3y +5)

Possible expression for height = (y – 1)

 

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Hope this will help you...

Answered by Anonymous
37

Step-by-step explanation:

(i) Volume : 3x² - 12x

↪3x²- 12x can be written as 3x(x-4) by taking 3x out of both the terms.

Possible expression for length = 3

Possible expression for breadth = x

Possible expression for height = (x-4)

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(ii) Volume: 12ky²+8ky-20k

↪12ky²+8ky- 20k can be written as 4k(3y²+2y-5) by taking 4k out of both the terms.

↪12ky²+8ky-20k = 4k(3y²+2y-5)

[Here, 3y²+2y-5 can be written as 3y²+5y-3y-5 using splitting the middle term method.]

↪ 4k(3y²+5y-3y-5)

↪ 4k[y(3y+5)-1(3y+5)]

↪ 4k(3y+5)(y-1)

Possible expression for length = 4k

Possible expression for breadth = (3y +5)

Possible expression for height = (y - 1)

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