Question

What are the possible expressions for the Dimensions of the cubiods whose volume Ky - 1 yo +40k​

Answer 1

Answer:

here function of volume is in y & k

so, here Function v(k,y)=12 ky

2

+8 ky−20 k

v(k,y)=4 k(3y

2

)+4k(2y)+4k(−5)

=4k(3y

2

+2y−5)

=4k(3y

2

+5y−3y−5)

=4k[(y)(3y+5)+(−1)(3y+5)]

=(4k)(y−1)(3y+5)

so, the dimension of the cuboids will be 4k,y−1 & 3y+5