what are the possible polynomial
expression for the dimensions of
the cuboids whose volumes are given below 3x^3 - 12x
Answers
Answered by
17
Volume of cuboid= l×b×h
Therefore, we need three factors of 3x³-12x
Let us factorize this polynomial.
Here,
3x³-12x= (3x)(x²-4)
So 3x is one factor.
x²-4 can also be written as (x)²-(2)²
We know that a²-b²= (a+b)(a-b)
Here, x²-4=(x)²-(2)²=(x+2)(x-2)
So, (x+2) and (x-2) are factors of this polynomial.
Therefore dimensions of the cuboid can be 3x, (x+2) and (x-2)
Hope it helps! Please mark it as 'Brainliest'!
Therefore, we need three factors of 3x³-12x
Let us factorize this polynomial.
Here,
3x³-12x= (3x)(x²-4)
So 3x is one factor.
x²-4 can also be written as (x)²-(2)²
We know that a²-b²= (a+b)(a-b)
Here, x²-4=(x)²-(2)²=(x+2)(x-2)
So, (x+2) and (x-2) are factors of this polynomial.
Therefore dimensions of the cuboid can be 3x, (x+2) and (x-2)
Hope it helps! Please mark it as 'Brainliest'!
Answered by
12
3x³ - 12x
3X(x² - 4)
3X(x² - 2²). [ a² - b² = (a-b)(a+b)]
3X(X+2)(x-2)
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