Chemistry, asked by ankitsinghkv2184, 1 year ago

what are the products formed when 1-butanol reacts with hot concentrated sulphuric acid

Answers

Answered by ScienceBranch
9

1-butanol or simply butanol undergoes dehydration when treated with Conc H2SO4. At this temperatures, each molecule of alcohol loses a water molecule and give butene as a product (C4H8).

C4H9-OH + conc. H2SO4 --> C4H8 + H20


sarithaomkaram80: The major product formed depends on the temperature of the reaction.

At 140 degree Celsius, the product is diethyl ether.
2C2H5OH = C2H5-O-C2H5 + H2O

At a higher temperature of around 170 degree Celsius, ethylene gas is produced.
C2H5OH = C2H4 + H2O.

In both these reactions, conc.H2SO4 acts as a dehydrating agent.
ScienceBranch: copied from google
ScienceBranch: i know
Answered by Anonymous
7

When 1-butanol ( C_{4}H_{9}OH ) is treated with hot concentrated sulphuric acid ( H_{2}SO_{4} ) , 1-Butene ( C_{4}H_{8} ) is formed .

C_{4}H_{9}OH + H_{2}SO_{4}  =>  C_{4}H_{8} + H_{2}O

  • Concentrated sulphuric acid ( H_{2}SO_{4} ) acts as a dehydrating agent .
  • Due to dehydration , the butanol loses a water molecule .
  • The molar mass of 1-butene is 56.108 g·mol−1 . It is used for the production of polyethylene .

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