Question

What are the root of the following quadratic equations p2-9=0

Answer 1

Answer:

p = -3, 3

Step-by-step explanation:

Given quadratic equation is

$p^2-9=0$

using identity

$a^2-b^=(a-b)(a+b)$

we get

$p^2-3^2=0$

(p-3)(p+3)=0

If p - 3 = 0, then p = 3

If p + 3 = 0,  then p =3