Question

what are the root of the quedratic equation x2+5x-14=0​

Answer 1

Answer:

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so here we go

Step-by-step explanation:

now here given quadratic equation is

x square+5x-14=0

ie x square+7x-2x-14=0

x(x+7)-2(x+7)=0

ie (x+7)(x-2)=0

so then,,

x+7=0 or x-2=0

ie x=-7 or x=2

hence -7 and 2 are required possible roots of above quadratic equation