Question

What are the roots of 6 x square - 6 x minus 2 is equal to zero

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

Given:

$6x^{2} - 6x - 2 = 0$

Here

a=6 , b=-6 and c=-2

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a}$

put the values

$x = \frac{ - ( - 6) \pm \sqrt{ {( - 6)}^{2} - 4(6)( -2)} }{2(6)} \\ = > \frac{6 \pm \sqrt{36 + 48} }{12} \\ = > \frac{6 \pm \sqrt{84} }{12}$

$x = \boxed{ \frac{6 + \sqrt{84} }{12}}$

and

$x = \boxed{ \frac{6 - \sqrt{84} }{12} }$