Question

what are the roots of a quadratic equation x^2 - 36 =?

Answer 1

Given: Quadratic Equation $x^{2} - 36$

To find: Roots (Zeroes)

Solution:

$x^{2} - 36$

• Write the number in the exponential form with an exponent of $2$.

$x^{2} - 6^{2}$

• Factor the expression by using the identity $(a^{2} - b^{2}) = (a-b)(a+b)$.

$(x-6)(x+6)$

• Set the equation equal to $0$.

$(x-6) = 0$

$(x+6)= 0$

• So, the equation becomes:

$x = 0+6\\x = 0-6$

• Add and subtract accordingly:

$x = 6\\x = -6$

Final Answer:

Hence, the roots of the quadratic polynomial $x^{2} - 36$ are $6$ and $-6$.