Question

What are the roots of quadratic eqatuion 3y

2

- 6y = 0

A) (0, -2) B) (0, 0) C) (0, 2) D) (2, 2)​

Answer 1

Answer:

3y^2 - 6y= 0

3y (y-2)=0

3y=0, y-2=0

y= 0/3=0 ,y=2

c (0,2)