Question

*What are the roots of the equation, x² - 7x + 12 = 0?*

1️⃣ (-3, -4)
2️⃣ (3, 4)
3️⃣ (6, 2)
4️⃣ (6, 1)​

Answer 1

Solution:

a=1,b=+7,c=+12

x=

2a

−b±

b

2

−4ac

x=

2×1

−(+7)±

7

2

−4×1×12

x=

2

−7±

49−48

x=

2

−7±1

x=

2

−7+1

or x=

2

−7−1

x=−3 or x=−4

Answer 2

Answer:

The roots are -3 and -4.

x² + 7x + 12 = x² + 3x + 4x + 12 = (x+3)(x+4)

Thus, x = -3 and -4

$\huge{ son \: prodigal}$