Question

what are the roots of the following Q.E?
x²+x-6=0​

Answer 1

Answer:

x²+x-6=0​

x^2+3x-2x+6=0

x(x+3)-2(x+3)=0

(x-2)(x+3)=0

x=2,x=-3

Step-by-step explanation:

Answer 2

Step-by-step explanation:

x2+x−6=0

Step 1: Factor left side of equation.

(x−2)(x+3)=0

Step 2: Set factors equal to 0.

x−2=0 or x+3=0

x=2 or x=−3