Question

What are the roots of the following quadratic 2x^2+6x+3=0

Answer 1

Answer:

We could find the nature of roots by finding Discriminant

By using the Formula

b^2-4ac

(-6)^2-4×2×3

36-24

12>0

Therefore 12>0 then the given quadratic eq. have distinct real roots

Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value

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Step-by-step explanation:

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