Question

what are the roots of the following quadratic equation x²-4=0​

Answer 1

Answer:

The roots of the quadratic equation x²-4=0​ is 2 or -2.

Step-by-step explanation:

Method 1:

a² - b² = (a -b) (a +b0

x²-4=0​

x²-(2)²=0​

(x - 2)(x + 2)= 0

x - 2 = 0 or x + 2 = 0

x = 2 or x = -2

Method 2:

x²-4=0​

x²=4

$x= \sqrt{4}$

x = ±2

x = 2 or x = -2

Answer 2

Answer:

The quadratic equation x²-4=$0$ is $x= 2$ and $-2$

Step-by-step explanation:

In accordance with the information provided in the question,

Given the data in question the quadratic equation x²-4=0

We know that the formula of the following quadratic equation

$\frac{-b\frac{+}{-}\sqrt{b^{2-4ac} } }{2a}$

Where a=1 , b=0 and c=-4

x= $\frac{-0\frac{+}{-}\sqrt{o^{2-4\times1\times(-4)} } }{2*1}$

x=$\frac{\frac{+}{-} \sqrt{16} }{2}$

x=$\frac{\frac{+}{-} 4}{2}$

x=$\frac{4}{2}$

x=$2$

So,

$x=\frac{-4}{2} \\x=-2$

Hence the  quadratic equation x²-4=$0$  is x =$2$ and $-2$