what are the roots of the quadratic equation 3x^2-6x+2=0
Answers
Answered by
0
Answer:1±√(1/3)
Step-by-step explanation:
x={-b±√(b²-4ac)}/2a
={6±√(36-24)}/6
=(6±√12)/6
=1±√(1/3)
Answered by
0
Answer:
1±√(1/3)
Step-by-step explanation:
x= (-b±√(b?-4ac) } /2a
= (6±√(36-24) } /6
= (6+√12) /6
= 1±√(1/3)
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