Math, asked by kritikaraj0286, 1 year ago

what are the roots of the quadratic equation 3x^2-6x+2=0​

Answers

Answered by eshankumar02122005
0

Answer:1±√(1/3)

Step-by-step explanation:

x={-b±√(b²-4ac)}/2a

={6±√(36-24)}/6

=(6±√12)/6

=1±√(1/3)

Answered by kingsolanki820
0

Answer:

1±√(1/3)

Step-by-step explanation:

x= (-b±√(b?-4ac) } /2a

= (6±√(36-24) } /6

= (6+√12) /6

= 1±√(1/3)

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