Question

what are the roots of the quadratic equation x²-2x -3=0​

Answer 1

Step-by-step explanation:

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

−

2

−

3

=

0

x^{2}-2x-3=0

x2−2x−3=0

=

1

a={\color{#c92786}{1}}

a=1

=

−

2

b={\color{#e8710a}{-2}}

b=−2

=

−

3

c={\color{#129eaf}{-3}}

c=−3

=

−

(

−

2

)

±

(

−

2

)

2

−

4

⋅

1

(

−

3

)

√

2

⋅

1

x=\frac{-({\color{#e8710a}{-2}}) \pm \sqrt{({\color{#e8710a}{-2}})^{2}-4 \cdot {\color{#c92786}{1}}({\color{#129eaf}{-3}})}}{2 \cdot {\color{#c92786}{1}}}

x=2⋅1−(−2)±(−2)2−4⋅1(−3)

2