what are the roots of the quadratic equation x2 =9
Answers
Step-by-step-explanation:-
Given :-
x² = 9
To find :-
Roots of Quadratic equation
Concept:-
Hence It is a Quadratic equation If has 2 roots
It should be in form of general of Quadratic equation
The general form of Quadratic equation = ax² +bx+c=0
So, convert into general form and we can find roots
Formula implemented:-
a²-b² = (a+b)(a-b)
___________________________
Solution:-
x² = 9
Transpose 9 to RHS
x² - 9 = 0
9 can be written as 3²
x² - 3² = 0
It is in form of a²-b²
We know formula Algebraic identity
a²- b² = (a + b)(a-b)
So,
x² - 3² = 0
(x + 3)(x-3) = 0
Equate each of factor to 0
x + 3 =0
x = -3
x -3 =0
x =3
So, the roots of x²-9 = +3 , -3
________________________
Know more about Quadratic equation
Quadratic equation has two roots
The nature of roots can be determined by Discriminant
Discriminant is denoted by d
Discriminant of Quadratic equation is b²-4ac
Nature of roots
If D>0 roots are real & distinct
D <0 Roots are complex & conjugate
D = 0 roots are real & equal
Answer:
Step-by-step-explanation:-
Given :-
x² = 9
To find :-
Roots of Quadratic equation
Concept:-
Hence It is a Quadratic equation If has 2 roots
It should be in form of general of Quadratic equation
The general form of Quadratic equation = ax² +bx+c=0
So, convert into general form and we can find roots
Formula implemented:-
a²-b² = (a+b)(a-b)
___________________________
Solution:-
x² = 9
Transpose 9 to RHS
x² - 9 = 0
9 can be written as 3²
x² - 3² = 0
It is in form of a²-b²
We know formula Algebraic identity
a²- b² = (a + b)(a-b)
So,
x² - 3² = 0
(x + 3)(x-3) = 0
Equate each of factor to 0
x + 3 =0
x = -3
x -3 =0
x =3
So, the roots of x²-9 = +3 , -3
________________________
Know more about Quadratic equation
Quadratic equation has two roots
The nature of roots can be determined by Discriminant
Discriminant is denoted by d
Discriminant of Quadratic equation is b²-4ac
Nature of roots
If D>0 roots are real & distinct
D <0 Roots are complex & conjugate
D = 0 roots are real & equal