Question

What are the roots of x^3+7x^2+16x+12?

Answer 1

Simplifying
x3 + 7x2 + 16x + 12 = 0

Reorder the terms:
12 + 16x + 7x2 + x3 = 0

Solving
12 + 16x + 7x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not

Answer 2

x^3 + 7x^2 + 16x + 12 = 0

x^3 + 2x^2 + 5x^2 + 10 x + 6x + 12 = 0

x^2 ( x + 2 ) + 5x ( x + 2 ) + 6 ( x + 2 ) = 0

( x + 2 ) ( x^2 + 5x + 6 ) = 0

( x + 2 ) ( x^2 + 3x + 2x + 6 ) = 0

( x + 2 ) [ x (x + 3 ) + 2 ( x + 3 ) ] = 0

( x + 2 ) ( x + 3 ) ( x + 2 ) = 0

x = - 2 or x = - 3