Math, asked by bunny8034, 5 months ago

What are the set of coincident zeroes which are possessed by x^4-2x^2+1

Answers

Answered by tyrbylent
1

Answer:

x = ± 1

Step-by-step explanation:

x² = n

If n² - 2n + 1 = (n - 1)² = 0 , then n = 1

x² = 1 ⇒ x = ± 1

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