Question

what are the slope and y-intercept in the graph of stopping potential against frequency of radiation for a certain photo emitter​

Answer 1

Answer:

Slope = h/e

y-intercept = -v₀(h/e)

Explanation:

Using conservation of energy, in such a condition,

Energy(by source,cell,etc) is equal to the kinetic energy(max) of the electrons.

⇒ eV = KE, where V is the stopping potential.

Using, KE(max) = hv - work function

                          = hv - Ф

                          = hv - hv₀

Therefore,

⇒ eV = hv - hv₀

⇒ V = v(h/e) - v₀(h/e)

Comparing this to y = mx + c. we get,

Slope = m = h/e

y-intercept = c = - v₀(h/e)

Answer 2

Answer:

Slope = h/e

y-intercept = -vo(h/e)

Explanation:

Using conservation of energy, in such a condition,

Energy(by source,cell,etc) is equal to the kinetic energy(max) of the electrons. ⇒ eV = KE, where V is the stopping potential.

Using, KE(max) = hv - work function

= hv - O

= hv - hvo

Therefore,

→ eV = hv - hvo

→ V = v(h/e) - vo(h/e)

Comparing this to y = mx + c. we get

Slope = m = h/e

y-intercept = c = - vo(h/e)

Explaination

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