Question

What are the solution(s) to the quadratic equation x2 – 25 = 0?

Answer 1

Answer:

-5 and 5

Step-by-step explanation:

x^2- 5^2

(x-5)(x+5)

so solution is-5 and +5

Answer 2

Answer:

Required solution of the given quadratic equation is $x = \pm5$

Step-by-step explanation:

Given,${x}^{2} - 25 = 0$

This is a quadratic equation of second degree,

${x}^{2} - {5}^{2} = 0$

$(x - 5)(x + 5) = 0$

If Product of two terms is zero then they are separately zero.

So,

$(x - 5) = 0 \\ x = 5$

Or,

$x + 5 = 0 \\ x = - 5$

Required value of x is $\pm5$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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