Question

What are the solutions of x² – 4x + 3 = 0? *

Answer 1

Answer:

solutions of $x^{2} -4x+3=0$ are

$x=3$  or  $x=1$

Step-by-step explanation:

To find the solutions of the polynomial we have an equation

$x=\frac{-b}{2a}$±$\frac{\sqrt{b^{2}-4ac } }{2a}$.

We know the general form of the polynomial $ax^{2} +bx+c=0$, hence in the given equation, $a=1 , b=-4, c=3$

Now, substituting in the equation above we get,

$x=\frac{-(-4)}{2}$±$\frac{\sqrt{(-4)^{2}-4(1)(3) } }{2}$

  $=2$±$\frac{\sqrt{16-12} }{2}$

  $=2$±$1$

  $=2+1$   or   $2-1$

  $=3$  or  $1$

hence the values of $x$ are  $x=3$  or  $x=1$

Thank you