Math, asked by sreeramkorada2710, 1 year ago

What are the solutions to the quadratic equation 4x^2-9x-9=0?

Answers

Answered by papai5
20
4x^2-9x-9=0
4x^2-(6-6)x-9=0
4x^2-6x+6x-9=0
2x(2x-3)+3(2x-3)=0
2x+3=0,2x-3=0
or, x=-3/2,3/2
Answered by wifilethbridge
20

Answer:

x=\frac{-3}{4},x=3

Step-by-step explanation:

Given : 4x^2-9x-9=0

To Find: What are the solutions to the quadratic equation

Solution:

4x^2-9x-9=0

4x^2-12x+3x-9=0

4x(x-3)+3(x-3)=0

(4x+3)(x-3)=0

4x+3=0,x-3=0

x=\frac{-3}{4},x=3

Hence the solution to the quadratic equation is x=\frac{-3}{4},x=3

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