what are the steps for solving an equation with competing square method
Answers
Answer:
Step-by-step explanation:
first we have to check whether the ax square term is a perfect square or not if the first term is not then we have to multiply the term with the same value of a then we have to to find the value of b and add the square and subtract the square.
by this we get a equation with the identity (a+)^2 which we have to take and simplify the other b^2 we took before to take the value for eg
5/2 whole square then make it 25l4 and subtract with the c term.
the value you get should be sended to the other side and then we have square root both the sides.
if it is 3x-5/2= root 4 then simplify the root and we have to send -5/2 to the other side and put a +or- sign for root 4
with this we get 2 values
3x=5/2 + 2=7l2
3x=5/2-2= 3/2
to get the value of x in the given values then we have to divide the 7/3 and 5/3 with 3.
mark it as the brainliest!!!!
Lets take an example for better understanding
3x^2 - 5x + 2 =0
=> x^2 - 5/3x + 2/3 = 0
( ÷ the whole equation by coefficient )
=> x^2 - 5/3x = -2/3
( now add square of the coefficient of x on both sides ie, here it is (1/2 × 5/3)^2 = 25/36 )
=> x^2 -5/3x + 25/36 = -2/3 + 25/36
=> (x - 5/6)^2 = -24/36 + 25/36
[ x^2 -5/3x + 25/36 = (x - 5/6)^2 using (a+b)^2 identity ]
=> (x - 5/6)^2 = 1/36
=> x -5/6 = +/-1/6 ( rooting both sides)
When +1/6
x= 1/6 + 5/6 = 6/6 = 1
When - 1/6
x= -1/6 + 5/6 = 4/6
Hope it helped....