Question

what are the ten rational numbers between -3/4 and 5/6​

Answer 1

Step-by-step explanation:

$\huge \tt{\text{A} \blue{N} \orange{S} \pink{W} \green{E} \red{R}} :) :)$

LCM of -3/4 & 5/6 = 12

$\tt = > { \frac {- 3 \times 3}{4 \times 3} } \: nd \frac{5 \times 2}{6 \times 2}\\\tt{= > \frac{ - 9}{12}nd \frac{10}{12} }$

Now LCM = 11

$= > \frac{ - 9 \times 11}{12 \times 11} \: nd \: \frac{10 \times 11}{12 \times 11}\\= > \frac{ - 99}{132} \: nd \: \frac{110}{132}$

$\tt \blue{The \: 10 \: Rational \: Numbers \: are :- } \\ \frac{ - 98}{132} < \frac{ - 97}{132} <\frac{ - 97}{132} < \frac{ - 96}{132} <\frac{ - 95}{132} < \frac{ -94 }{132}\\ < \frac{ - 93}{13}\frac{ - 92}{132} < \frac{ - 91}{132} < \frac{ - 90}{132} < \frac{89}{132} < \frac{88}{132}$

Hope it helpful.....☃️✌️

Answer 2

Answer:

:):)

LCM of -3/4 & 5/6 = 12

\begin{gathered} \tt = > { \frac {- 3 \times 3}{4 \times 3} } \: nd \frac{5 \times 2}{6 \times 2}\\\tt{= > \frac{ - 9}{12}nd \frac{10}{12} }\end{gathered}

=>

4×3

−3×3

nd

6×2

5×2

=>

12

−9

nd

12

10

Now LCM = 11

\begin{gathered} = > \frac{ - 9 \times 11}{12 \times 11} \: nd \: \frac{10 \times 11}{12 \times 11}\\= > \frac{ - 99}{132} \: nd \: \frac{110}{132} \end{gathered}

=>

12×11

−9×11

nd

12×11

10×11

=>

132

−99

nd

132

110

\begin{gathered} \tt \blue{The \: 10 \: Rational \: Numbers \: are :- } \\ \frac{ - 98}{132} < \frac{ - 97}{132} < \frac{ - 97}{132} < \frac{ - 96}{132} < \frac{ - 95}{132} < \frac{ -94 }{132}\\ < \frac{ - 93}{13}\frac{ - 92}{132} < \frac{ - 91}{132} < \frac{ - 90}{132} < \frac{89}{132} < \frac{88}{132} \end{gathered}

The10RationalNumbersare:−

132

−98

<

132

−97

<

132

−97

<

132

−96

<

132

−95

<

132

−94

<

13

−93

132

−92

<

132

−91

<

132

−90

<

132

89

<

132

88