Question

What are the three consecutive integers whose sum is 63

Answer 1

Let x , x + 1 , x + 2 are three

consecutive integers ,

Sum of three numbers = 63 ( given )

=> x + x + 1 + x + 2 = 63

=> 3x + 3 = 63

=> 3x = 63 - 3

=> 3x = 60

=> x = 60/3

=> x = 20

Therefore ,

Required 3 integers are ,

x = 20 ,

x + 1 = 20 +1 = 21 ,

x + 2 = 20 +2 = 22

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Answer 2

Answer:

Step-by-step explanation:

Let the three consecutive numbers be x x+1 x+2

According to the question

x+x+1+x+2=63

3x+3 =63

3x =63-3=60

x =60÷3

=20

Therefore the three consecutive numbers are 20,21(20+1),22(20+2)

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