Math, asked by kiran91shiva, 7 hours ago

What are the three consecutive lowest numbers that are divisible by cubes of 5 , 2 and 3 ?

Answers

Answered by amitnrw
2

Given : numbers that are divisible by cubes of 5 , 2 and 3

To Find : three consecutive lowest numbers

Solution:

2 ,3  and 5 are prime numbers

Hence their cubes would be co prime with each other

2³ = 8

3³ = 27

5³  125

Lowest number which will be divisible by these will be LCM of these numbers

LCM ( 8 , 27 , 125) = 8 * 27 * 125

= (30)³

= 27000

Lowest number = 27000

next two numbers can be 27000 * 2  and 27000 * 3

Hence 27000 , 54000  and 81000 are  three consecutive lowest numbers that are divisible by cubes of 5 , 2 and 3  

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