Question

What are the three rules of vedic maths with 5 examples of each?

Answer 1

Vedic maths is based on 16 sutras and 13 subsutras. It can be used to solve maths problems with ease. Using bases, (these are powers of 10) as friendly numbers makes multiplication very easy. Ex. 109 * 108 = 11172. All you have to do is add the surplus over 100 of one number to the other whole number (108+9) 0r (109+8) to get 117 and then multiply these surpluses (9*8) = 17. If the numbers are below 100 you subtract the differences from hundred, Ex. 96*93 96–7 or 93–4 = 89 and 7*4=28. Answer 8928. If you have 1 number over 100 and 1 below: 107 * 92, Here the differences are positive and negative. 107 is 7 more than 100 and 92 is minus *8. For the first part you add +7 to 92 or minus from 107 =99. the second part is negative - 7* -8 = -56. So add 2 zeroes to 9900 and subtract 56 =9844. Multiply by 11. 34, 45, 62, 81. Just add the two digits and place it in the middle. 34=374, 45=495. 62=686. 81=891. If the addition of the 2 digits exceeds 9 carry the 10’s digit to the left. 87*11, 8+7=15 so put 5 before 7 and add 1 to 8. 957.

Answer 2

Answer:

The three rules of vedic maths are:

1) Ekadhikena purvena

This means Square of numbers ending in five 15^2 shall answered end up in 25 with tensing answer as taking remaining digits other than 5 adding 1 to it and multiplying.

Eg: 1+1=2. (1*2=2) 15^2=225. 195^2=(19*20)/25=38025

2) if the units place does adds up to 10 with remaining digits being same then too apply the same result.

Eg: 23*27 here 3+7=10, remaining digit is 2. So, (2*3)/21=621 this uses the antyordasakepi rule. 33*38=(3*4)/24=1224

3)Yavadunamtavadunikrutyam vargamca yojayet

13^2=(13+3)/3^2=169. 13 is three more than ten. So 13+3 is 16 and 3^2 is 9. 113^2 =(113+13)/13^2=(126)/169 but the base 100 has two zeros so 1 of 169 has to be carried to 126 so 12769 is the square of 113.