Question

what are the two angles of progection of a projectile projected with velocity 30 metre per second so that the horizontal range is 45 m
(take g=10 m ^-2)



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Answer 1

here is your answer :-

Horizontal Range Hence, horizontal range is inversely proportional to the acceleration due to gravity

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Answer 2

Answer:

Range =  

45 = tex] \frac{ 30^{2} sin(2 \alpha )}{10} [/tex]

⇒45 =  

⇒ 45 = 90 sin(2α)

⇒sin(2α) = 1/2

⇒ 2α = 30° or 150°

⇒ α = 15° or 75°

Explanation:

see the attacment if you dont understand