Question

What are the two angles of projection of a projectile projected with velocity 30m/s, so that the horizontal range is 45m. Take, g = 10m/s​

Answer 1

Answer:

Explanation:

R = u^2 sin2theta/g

=> sin2theta = 45 * 10/ 900

=> sin 2theta = 1/2

2theta = pi/6 or 5 pi/6

theta = 15 degrees or 75 degrees.