Question

What are the two numbers that are in the ratio of 9 : 7 and their difference is 36?​

Answer 1

Answer:

The two numbers are 162 and 126 respectively.

Step-by-step explanation:

Consider, the two numbers be 9x and 7x

According to given condition,

9x-7x=36

2x=36

x=36/2

x=18

hence,

1st number is 9x=9×18=162

2nd number is 7x = 7×18=126

Therefore, the two numbers are 162 and 126 respectively.

Answer 2

Let assume that, the First number is x

And the other one is y

So As according to First case

The Ratio Of two numbers is 9 : 7

So, we can write it like this,

$\sf \frac{x}{y} = \frac{9}{7}$

$\sf x = \frac{9}{7} y$

And According to Second case

Their Difference Is 36.

So, x - y = 36

Here, we can put the value of x according to the first case

Hence,

$\sf \bigg( \frac{9}{7}y \bigg) - y = 36$

$\sf \frac{9y - 7y}{7} = 36$

$\sf \frac{2y}{7} = 36$

$\sf 2y = \frac{36}{7}$

$\sf y = \frac{36}{2 × 7}$

$\sf y = \frac{\cancel{36}^{\: \: 18 × \cancel{2} }}{\cancel{2} × 7}$

$\underline{ \boxed{\sf y = \frac{18}{7} }}$

Now, For x

$\sf x = \frac{9}{7} y$

$\sf x = \frac{9}{7} × \bigg( \frac{18}{7}\bigg)$

$\underline{ \boxed{\sf x = \frac{162}{49} }}$

First number is $\underline{ \boxed{\sf x = \frac{162}{49} }}$

Second number is $\underline{ \boxed{\sf y = \frac{18}{7} }}$

I hope it helps you ❤️✔️