what are the two numbers that subtract to 2 and multipliys to 80?
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Answer:
8 and 10 or (-10) and (-8)
Step-by-step explanation:
let the 1st no be x and 2nd no be y
x-y=2
y=x+2
(x)×(y)=80
(x)×(x+2)=80
x²+2x=80
x²+2x-80=0
x²-8x+10x-80=0
x(x-8) +10(x-8) =0
(x-8)(x+10) are the roots of the polynomial
x-8=0 , x+10 =0
x=8 , x=(-10)
hence the two no.s are (8 and 10) or (-10and -8)
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