What are the two types of charges and also state the interactive forces between them
Answers
Answer:
There are two types of electric charge: positive and negative (commonly carried by protons and electrons respectively). Like charges repel each other and unlike charges attract each other.
Explanation:
The Coulomb force (F), also called electrostatic force or Coulomb interaction, states that the magnitude of the electrostatic force of interaction between two point electrical charges (q1, q2) is directly proportional to the scalar multiplication of the magnitudes of electrical charge and inversely proportional to the square of the distance (r) between them.
The Coulomb force is along the straight line joining them. If the two electrical charges have the same sign, the electrostatic force between them is repulsive; if they have different signs, the force between them is attractive.
The mathematical expression of Coulomb’s law is:
F=kq1q2r2 ..... (i)
where:
F [N] – Coulomb force
q1, q2 [C] – electrical charges
r [m] – distance between electrical charges
k [F/m] – is called the Coulomb’s constant, or electric force constant or electrostatic constant.
The value of Coulomb’s constant is calculated as:
k=14πε0 .................(2)
where ε0 is the electrical permittivity of free space (vacuum).
The electrical permittivity is a constant, of value:
ε0=8.854187817⋅10−12Fm
The unit of measurement for electrical permittivity is Farad per meter.
Replacing the value of electrical permittivity in equation (2), we can calculate the value of Coulomb’s constant:
k=8.987552⋅109Nm2C2
If the electrical charges are placed in another medium, water for example, instead of using the permittivity of vacuum, we need to use the absolute permittivity ε which is the product between the permittivity of vacuum ε0 and relative permittivity εr.
ε=ε0⋅εr(3)
In this case, the Coulomb constant will be:
k=14πε(4)
Example. Calculate the Coulomb force between two electrons in water, at the distance of 1 mm from each other.
q1rε0=q2=1.6⋅10−^19 c
r=0.001m
ε0=8.854187817⋅10−12
The relative permittivity of water at 20 °C is:
εr=80.1
The Coulomb force will be: