Question

what are the values if iota squre and iota cube plzz reply fast

Answer 1

i^2=-1
i^3=-i
hope this helps

Answer 2

Answer:

$i^{2}=-1\\i^{3}=-i$

Step-by-step explanation:

$The \: imaginary \: number\\i\: is \: defined \: solely \\by \: the \: property \:that\\its\:square \:is \: -1$

$i^{2}=-1$

$i^{3}= i^{2}\times i\\=(-1) \times i\\=-i$

Therefore,

$i^{2}=-1\\i^{3}=-i$

•••♪