Question

What are the values of A,B and C if A+B+C=13 and AxBxC=36?

Answer 1

Answer:

s

Step-by-step explanation:

solve 13×36=468 answer

Answer 2

Given,

A+B+C = 13

A×B×C = 36

To find,

The values of A, B and C.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

First of all, we have to the prime factorization of the product of the given three numbers, in order to find out the numbers.

prime factorization :

36 = 2×2×3×3

Now, there are three numbers in the given product/sum, and thats why, any two numbers of the above mentioned factorization will be multiplied to each other to form a single number which will be considered as the third number.

Probability 1 :

Third number = 2×2 = 4

Sum of the numbers = 4+3+3 = 10 ≠ 13

Probability 2 :

Third number = 2×3 = 6

Sum of the numbers = 2+6+3 = 11 ≠ 13

Probability 3 :

Third number = 3×3 = 9

Sum of the numbers = 2+2+9 = 13 (Right probability)

So,

if A,B,C have values of 2,2,9, then both the values of A+B+C and A×B×C will be satisfied.

Hence, values are 2,2,9