Question

What are the zeroes of of
4x2 – X – 3​

Answer 1

Answer:

$4 {x}^{2} - x - 3 = 0 \\ \\ 4 {x}^{2} - 4x + 3x - 3 = 0 \\ \\ 4x(x - 1) + 3(x - 1) = 0 \\ \\ (x - 1) \: \: (4x + 3) = 0 \\ \\ x = 1 \: \: \: or \: \: = \frac{ - 3}{4}$

Answer 2

Answer:

$\frac{ - 3}{4} \: and \: 1$

Step-by-step explanation:

4 x² - x - 3 = 0

4x² - (4-3)x -3 = 0

4x² - 4x + 3x - 3 = 0

4x(x-1) +3(x-1) = 0

(4x + 3) (x-1)=0

if 4x + 3 =0

$then \: x = \frac{ - 3}{4}$

if x-1 = 0

$then \: x = 1$

$so \: zeroes \: of \: 4 {x}^{2} - x - 3 \: are \: \frac{ - 3}{4} \: and \: 1$