What are the zeroes of polynomial (x-1)(x-2)(x-3)
Answers
Answered by
2
(x-1)(x-2)(x-3)=0
3x-6=0
3x=6
x=2
3x-6=0
3x=6
x=2
Answered by
8
Hey !!!
(x - 1 ) ( x - 2 ) ( x - 3 ) = 0
x - 1 = 0
x = 1
or, x - 2 = 0
x = 2
or ,
x - 3 = 0
x = 3
hence , 1 , 2 , 3 are zero of given polynomial
for verification substitute the value
p(x ) = ( x - 1 ) ( x - 2 ) ( x -3 )
p( 1) = 1 - 1 (x - 2 ) ( x - 3 )
p(1) = 0
similarly ,
p(2) = 0
and also p(3) = 0
hence , my solution is verified
__________________
Hope it helps you !!
@Rajukumar111
(x - 1 ) ( x - 2 ) ( x - 3 ) = 0
x - 1 = 0
x = 1
or, x - 2 = 0
x = 2
or ,
x - 3 = 0
x = 3
hence , 1 , 2 , 3 are zero of given polynomial
for verification substitute the value
p(x ) = ( x - 1 ) ( x - 2 ) ( x -3 )
p( 1) = 1 - 1 (x - 2 ) ( x - 3 )
p(1) = 0
similarly ,
p(2) = 0
and also p(3) = 0
hence , my solution is verified
__________________
Hope it helps you !!
@Rajukumar111
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