Question

what are the zeroes of polynomial x²+2x-19

Answer 1

factors of x²+2x-19

= -b+-√b²- 4ac÷2a
= -2+-√(2)²- 4×1×19÷2
= -2+-√4 - 76÷2
= -2+-√-72÷2
= -2+-√2×2×2×3×3÷2
= -2+-2×3√2÷2
= -2+-6√2÷2
= -2(1+√2÷2