Question

*What are the zeroes of polynomial "x² - 7"?

Answer 1

Answer:

x² - 7 = 0. Write both terms in perfect square:

x² - (√7)² = 0. Apply a² - b² = (a + b)(a - b)

(x - √7) (x + √7) = 0. Apply zero product property:

Step-by-step explanation:

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