what are the zeroes of the polynomial p(x)=4x^2 -49?
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Answered by
3
4x^2-49=0
4x^2=49
x^2=49/4
x=underroot 49/4
x=7/2
4x^2=49
x^2=49/4
x=underroot 49/4
x=7/2
Answered by
6
4x^2-49=0
(2x)^2-7^2=0
(2x+7)(2x-7)=0
2x+7=0 or 2x-7=0
2x=-7 or 2x=7
x=-7/2 and 7/2 are zeros
(2x)^2-7^2=0
(2x+7)(2x-7)=0
2x+7=0 or 2x-7=0
2x=-7 or 2x=7
x=-7/2 and 7/2 are zeros
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