Question

what are the zeroes of the polynomial P(x) = 6x² - 7x -3​

Answer 1

Answer:

6x²-7x-3

=6x²-9x+2x-3=0

=3x(2x-3)+1(2x-3)=0

=(2x-3) (3x-1) =0

x=3/2 , x=-1/3

Answer 2

Answer:

6x²-7x-3

=6x²-9x+2x-3=0

=3x(2x-3)+1(2x-3)=0

=(2x-3) (3x-1) =0

x=3/2 , x=-1/3

Step-by-step explanation: