Question

What are the zeroes of the Polynomial p(x)=x2+7x+10 a. (2) , (-5) b. (-2) , (5) c. (2) , (5) d. (-2) , (-5)

Answer 1

Answer:

d -2 and -5 is correct one

100% correct

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Answer 2

By putting a.(2) , (-5)

p(2)=2(2)+7(2)+10

=4+14+10

=58

p(-5)=(-5)(2)+7(-5)+10

=-10-35+10

=55

Not equal to zero so a.(2) , (-5) are not zeros of polynomial

By putting b.(-2) ,(5)

p(-2)=-2(2)+7(-2)+10

=-4-14+10

=0

p(5)=5(2)+7(2)+10

=10+14+10

=34

p(-2) is the zeros of the polynomial and p(5) are not the zeros of the polynomial

By Putting c.(2),(5)

p(2)=2(2)+7(2)+10

=4+14+10

=28

p(5)=2(5)+7(5)+10

=10+35+10

=55

not equal to zero so p(2),(5) are not the zeros of the polynomial

By Putting d.(-2),(-5)

p(-2)=(-2)(2)+7(2)+10

=-4+14+10

=0

p(-5)=(-5)(5)+7(5)+10

=-25+35+10

=0

equal to zero so p(-2),(-5) are the zeros of the polynomial

so,d. (-2),(-5) are the zeros of the polynomial

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