Question

What are the zeroes of the polynomial x square + 6x + 9 *
(1 point)
3,3
-3,-3
-3,3
3,-3​

Answer 1

• Option (B) is correct answer.

Explanatory Solvation ⬇⬇⬇

$\huge \bf {x}^{2} + 6x + 9 \\ \\ \tt = > {x}^{2} + 3x + 3x + 9 \\ = > \tt x(x + 3) + 3(x + 3) \\ = > \sf ( \red{x + 3})( \red{x + 3}) \\ \\ \sf \therefore \: \: \: \: \: \: x = ( \red{- 3 })\: \: \: \: \: or \: \: \: \: ( \red{- 3})$

Answer 2

HERE IS YOUR ANSWER MATE.....;

$= > x {}^{2} + 6x + 9 = 0$

$= > x {}^{2} + 3x + 3x + 9 = 0$

$= > x(x + 3) + 3(x + 3) = 0$

$= > (x + 3)(x + 3)$

$x = - 3$

$x = - 3$

HOPE IT'S HELPFUL....:-)