What are the zeroes of the polynomial x2+6x+9
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x^2 +6x+9=0
x^2 +3x+3x+9=0
x(x+3)+3(x+3)=0
(x+3)^2 =0
so, zeros are :x= -3,-3
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Answer:
x^2 + 6x + 9
x^2 + 3x + 3x + 9
x ( x + 3 ) + 3 ( x + 3 )
( x + 3 ) ( x + 3 )
ᴢᴇƦᴏᴇS ᴏҒ ᴛʜᴇ ᴘᴏʟʏɴᴏᴍɪᴀʟS : [ -3 , -3 ]
( x + 3 )
x = -3
↳ - 3 ✓
( x + 3 )
x = -3
↳ -3 ✓
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