Question

what are the zeroes of the quadratic polynomial x²+7x+12​

Answer 1

Answer:

-4 , -3

Step-by-step explanation:

x²+7x+12 = x²+4x+3x+12 = x(x+4)+3 (x+4) = (x+4)(x+3)

if x+4 = 0 then x= -4

if x+3 = 0 then x= -3