Math, asked by devyani72, 11 months ago

what are the zeroes of the (x^2 -2)​

Answers

Answered by LovelyG
2

Answer :

x {}^{2}  - 2 \\  \\ (x) {}^{2}  - ( \sqrt{2} ) {}^{2}  \\  \\ (x +  \sqrt{2} )(x -  \sqrt{2} )

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Answered by babushall
3

given x^2-2=0

x^2=2

x=+√2 or x=-√2

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