Question

What are the zeros of 3÷x+x=5?

Answer 1

 the attachment below is the solution

Answer 2

$\frac{3}{x}$ + x = 5

3 + $x^{2}$ = 5x

$x^{2}$ - 5x +3 = 0

Quadratic formula:

$\frac{ -b + or - \sqrt{ b^{2} } -4ac}{2a}$

So, a = 1 ,b = -5 and c = 3

$\frac{5 + or - \sqrt{25-4(1)(3)} }{2(1)}$

$\frac{5 + or - \sqrt{13} }{2}$

The zeros are $\frac{5+ \sqrt{13} }{2}$ and $\frac{5- \sqrt{13} }{2}$