Question

what are the zeros of 6x2-5x-11​

Answer 1

Correct Question :- Find the zero's of 6x² - 5x - 11.

Correct Answer :-

We can solve the given expression as follows;

$\sf{6x ^ { 2 } -5x-11=0}$

$\to \sf{\left(6x^{2}-11x\right)+\left(6x-11\right) }$

$\to \sf{x\left(6x-11\right)+6x-11 }$

$\to \sf{\left(6x-11\right)\left(x+1\right) }$

$\leadsto { \boxed{ \pmb{ \sf{ \red{x=\frac{11}{6} \: \: or \: \: x=-1 }}}}}$

∴ Hence, the zero's for 6x² - 5x - 11 will be $ \bf{x=-1}$.

Answer 2

Given :

6x² - 5x - 11

To Find :

Zeros of the polynomial.

Solution :

Now , using splitting the middle term method.

⇨ 6x² - 5x - 11

⇨ 6x² - 11x + 6x - 11

⇨ x ( 6x - 11 ) + 1 ( 6x - 11 )

⇨ ( x + 1 ) ( 6x -11 )

⇨ x + 1 = 0 ; 6x - 11 = 0

⇨ x = -1 ; x = 11/6

Zeros of the polynomial is -1 and 11/6.