Question

what are the zeros of p(x)=5-x sq.? ​

Answer 1

Step-by-step explanation:

$p(x) = 5 - {x}^{2}$

Zeros are,

$5 - {x}^{2} = 0$

${x}^{2} = 5$

$x = + \sqrt{5} or \: - \sqrt{5}$

HOPE it will HELP you✌️

PLEASE mark the answer as BRAINLIEST. ✍️

Answer 2

Step-by-step explanation:

$5 - {x}^{2} = 0 \\ 5 = {x}^{2} \\ {x}^{2} = + - \sqrt{5}$

hope it helps please mark me as brainliest