Question

What are the zeros of polynomial 4x^2 + 8x​

Answer 1

Answer:

"

zeroes =

$\huge \tt \color{maroon}{0 , - 2}$

Step-by-step explanation:

zeroes of 4x² + 8x

=> 4x² + 8x

=> 4x(x + 2)

[taking 4x common]

=> (4x) (x + 2)

.

so zeroes -

.

zero 1.

4x = 0

=> x = 0/4

=> x = 0

.

zero 2.

x + 2 = 0

=> x = -2

.

Hence zeroes = 0 and -2

.

hope it helps.